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Q.No: 1
Test Name : CAT Paper 2004

Directions for questions 21 to 26: Each question is followed by two statements, A and B. Answer each question using the following instructions.
Choose (1) if the question can be answered by using one of the statements alone but not by using the other statement alone.
Choose (2) if the question can be answered by using either of the statements alone.
Choose (3) if the question can be answered by using both statements together but not by either statement alone.
Choose (4) if the question cannot be answered on the basis of the two statements.


Zakib spends 30% of his income on his children's education, 20% on recreation and 10% on healthcare. The corresponding percentage for Supriyo are 40%, 25%, and 13%. Who spends more on children's education?
A. Zakib spends more on recreation than Supriyo.
B. Supriyo spends more on healthcare than Zakib.

A
1
B
2
C
3
D
4
Solution:
Q.No: 2
Test Name : CAT Paper 2004

Directions for questions 21 to 26: Each question is followed by two statements, A and B. Answer each question using the following instructions.
Choose (1) if the question can be answered by using one of the statements alone but not by using the other statement alone.
Choose (2) if the question can be answered by using either of the statements alone.
Choose (3) if the question can be answered by using both statements together but not by either statement alone.
Choose (4) if the question cannot be answered on the basis of the two statements.


Four candidates for an award obtain distinct scores in a test. Each of the four casts a vote to choose the winner of the award. The candidate who gets the largest number of votes wins the award. In case of a tie in the voting process, the candidate with the highest score wins the award. Who wins the award?
A. The candidates with top three scores each vote for the top score amongst the other three.
B. The candidate with the lowest score votes for the player with the second highest score.

A
1
B
2
C
3
D
4
Solution:
Q.No: 3
Test Name : CAT Paper 2004

Directions for questions 21 to 26: Each question is followed by two statements, A and B. Answer each question using the following instructions.
Choose (1) if the question can be answered by using one of the statements alone but not by using the other statement alone.
Choose (2) if the question can be answered by using either of the statements alone.
Choose (3) if the question can be answered by using both statements together but not by either statement alone.
Choose (4) if the question cannot be answered on the basis of the two statements.


In a class of 30 students, Rashmi secured the third rank among the girls, while her brother Kumar studying in the same class secured the sixth rank in the whole class. Between the two, who had a better overall rank?
A. Kumar was among the top 25% of the boys merit list in the class in which 60% were boys.
B. There were three boys among the top five rank holders, and three girls among the top ten rank holders.

A
1
B
2
C
3
D
4
E
5
Solution:
Q.No: 4
Test Name : CAT Paper 2004

Directions for questions 21 to 26: Each question is followed by two statements, A and B. Answer each question using the following instructions.
Choose (1) if the question can be answered by using one of the statements alone but not by using the other statement alone.
Choose (2) if the question can be answered by using either of the statements alone.
Choose (3) if the question can be answered by using both statements together but not by either statement alone.
Choose (4) if the question cannot be answered on the basis of the two statements.


Tarak is standing 2 steps to the left of a red mark and 3 steps to the right of a blue mark. He tosses a coin. If it comes up heads, he moves one step to the right; otherwise he moves one step to the left. He keeps doing this until he reaches one of the two marks, and then he stops. At which mark does he stop?
A. He stops after 21 coin tosses.
B. He obtains three more tails than heads.

A
1
B
2
C
3
D
4
Solution:
Q.No: 5
Test Name : CAT Paper 2004

Directions for questions 21 to 26: Each question is followed by two statements, A and B. Answer each question using the following instructions.
Choose (1) if the question can be answered by using one of the statements alone but not by using the other statement alone.
Choose (2) if the question can be answered by using either of the statements alone.
Choose (3) if the question can be answered by using both statements together but not by either statement alone.
Choose (4) if the question cannot be answered on the basis of the two statements.


Ravi spent less than Rs. 75 to buy one kilogram each of potato, onion, and gourd. Which one of the three vegetables bought was the costliest?
A. 2 kgs potato and 1 kg gourd cost less than 1 kg potato and 2 kg gourd.
B. 1 kg potato and 2 kgs onion together cost the same as 1 kg onion and 2 kgs gourd.

A
1
B
2
C
3
D
4
Solution:
Q.No: 6
Test Name : CAT Paper 2004

Directions for questions 21 to 26: Each question is followed by two statements, A and B. Answer each question using the following instructions.
Choose (1) if the question can be answered by using one of the statements alone but not by using the other statement alone.
Choose (2) if the question can be answered by using either of the statements alone.
Choose (3) if the question can be answered by using both statements together but not by either statement alone.
Choose (4) if the question cannot be answered on the basis of the two statements.


Nandini paid for an article using currency notes of denominations Re. 1, Rs. 2, Rs. 5, and Rs. 10 using at least one note of each denomination. The total number of five and ten rupee notes used was one more than the total number of one and two rupee notes used. What was the price of the article?
A. Nandini used a total of 13 currency notes.1
B. The price of the article was a multiple of Rs. 10.

A
1
B
2
C
3
D
4
Solution:
Q.No: 7
Test Name : CAT Paper 2007

Directions for Questions 30 to 33: Each question is followed by two statements, A and B.
Answer each question using the following instructions:
Mark (1) if the question can be answered by using the statement A alone but not by using the statement B alone.
Mark (2) if the question can be answered by using the statement B alone but not by using the statement A alone.
Mark (3) if the question can be answered by using either of the statements alone.
Mark (4) if the question can be answered by using both the statements together but not by either of the statements alone.
Mark (5) if the question cannot be answered on the basis of the two statements.


ln a football match, at the half-time, Mahindra and Mahindra Club was trailing by three goals. Did it win the match?
A. In the second-half Mahindra and Mahindra Club scored four goals.
B. The opponent scored four goals in the match.

A
(1)
B
(2)
C
(3)
D
(4)
E
(5)
Solution:
Q.No: 8
Test Name : CAT Paper 2003 (R)
Directions for questions 127 and 128: Answer the questions on the basis of the following information. Shown below is the layout of major streets in a city.



Two days (Thursday and Friday) are left for campaigning before a major election, and the city administration has received requests from five political parties for taking out their processions along the following routes.
Congress: A-C-D-E        BJP: A-B-D-E        SP: A-B-C-E
BSP: B-C-E               CPM: A-C-D

Street B-D cannot be used for a political procession on Thursday due to a religious procession. The district administration has a policy of not allowing more than one procession to pass along the same street on the same day. However, the administration must allow all parties to take out their procession during these two days.

Congress procession can be allowed

A
only on Thursday
B
only on Friday
C
on either day
D
only if the religious procession is cancelled
Solution:
Congress – Thursday              BJP – Friday
SP – Thursday                    BSP – Friday
CPM – Friday
Congress procession can only be allowed on Thursday.
Q.No: 9
Test Name : CAT Paper 2003 (R)
Directions for questions 127 and 128: Answer the questions on the basis of the following information. Shown below is the layout of major streets in a city.



Two days (Thursday and Friday) are left for campaigning before a major election, and the city administration has received requests from five political parties for taking out their processions along the following routes.
Congress: A-C-D-E        BJP: A-B-D-E        SP: A-B-C-E
BSP: B-C-E               CPM: A-C-D

Street B-D cannot be used for a political procession on Thursday due to a religious procession. The district administration has a policy of not allowing more than one procession to pass along the same street on the same day. However, the administration must allow all parties to take out their procession during these two days.

Which of the following is NOT true?

A
Congress and SP can take out their processions on the same day.
B
The CPM procession cannot be allowed on Thursday.
C
The BJP procession can only take place on Friday.
D
Congress and BSP can take out their processions on the same day.
Solution:
Congress – Thursday              BJP – Friday
SP – Thursday                    BSP – Friday
CPM – Friday
According to the given table, statement (4) is not true.
Q.No: 10
Test Name : CAT 2019 Actual Paper Slot 1
Question Numbers (43 to 46): Answer the questions on the basis of the information given below.

A new game show on TV has 100 boxes numbered 1, 2, . . . , 100 in a row, each containing a mystery prize. The prizes are items of different types, a, b, c, . . . , in decreasing order of value. The most expensive item is of type a, a diamond ring, and there is exactly one of these. You are told that the number of items at least doubles as you move to the next type. For example, there would be at least twice as many items of type b as of type a, at least twice as many items of type c as of type b and so on. There is no particular order in which the prizes are placed in the boxes.

What is the minimum possible number of different types of prizes?

Solution:
It is given that the most expensive item is a diamond ring of type a and there is exactly one of these. Since the item b should be at least twice. The minimum number of items will be obtained when a = 1 and b = 99, which means there are only two different types of items.
Q.No: 11
Test Name : CAT 2019 Actual Paper Slot 1
Question Numbers (43 to 46): Answer the questions on the basis of the information given below.

A new game show on TV has 100 boxes numbered 1, 2, . . . , 100 in a row, each containing a mystery prize. The prizes are items of different types, a, b, c, . . . , in decreasing order of value. The most expensive item is of type a, a diamond ring, and there is exactly one of these. You are told that the number of items at least doubles as you move to the next type. For example, there would be at least twice as many items of type b as of type a, at least twice as many items of type c as of type b and so on. There is no particular order in which the prizes are placed in the boxes.

What is the maximum possible number of different types of prizes?

Solution:
It is given that the most expensive item is a diamond ring of type a and there is exactly one of these. Since the number of items of type b should be at least twice of that of a and the number of items of type c should be at least twice of that of b and so on. So the maximum number of different types of items of a, b and c will be obtained when a = 1, b = 2, c = 4, d = 8, e = 16, f = 69. Hence the maximum number of different types of items will be 6.
If the number of items is 7, then the minimum number of prizes should be 1 + 2 + 4 + 8 + 16 + 32 + 64 = 127 which is more than 100. Hence, 6 is the answer.
Q.No: 12
Test Name : CAT 2019 Actual Paper Slot 1
Question Numbers (43 to 46): Answer the questions on the basis of the information given below.

A new game show on TV has 100 boxes numbered 1, 2, . . . , 100 in a row, each containing a mystery prize. The prizes are items of different types, a, b, c, . . . , in decreasing order of value. The most expensive item is of type a, a diamond ring, and there is exactly one of these. You are told that the number of items at least doubles as you move to the next type. For example, there would be at least twice as many items of type b as of type a, at least twice as many items of type c as of type b and so on. There is no particular order in which the prizes are placed in the boxes.

Which of the following is not possible?

A
There are exactly 75 items of type e.
B
There are exactly 45 items of type c.
C
There are exactly 30 items of type b.
D
There are exactly 60 items of type d.
Solution:
Option 1: There are exactly 75 items of type e.
a = 1, b = 2, c = 4, d = 8, e = 85. Here the maximum value of e = 85. Hence it can take the value 75.
An example of such case is a = 1, b = 2, c = 4, d = 18, e = 75
Option 2: There are exactly 45 items of type c.
Since the value of d should be at least 90, it means that d is not present because 45 + 90 will be more than 100(maximum number of items). Only a, b and c are present.
The maximum value of b = 22 and a = 1,
but 45 + 22 + 1 = 68, which is less than 100. So this case is not possible.
Option 3: There are exactly 30 items of type b. a = 1, b = 30 and c = 69. Hence this case is also possible.
Option 4: There are exactly 60 items of type d. d = 60, c = 30, b = 9 and a = 1. a + b + c + d = 100. Hence, this case is possible.
2 is the answer.
Q.No: 13
Test Name : CAT 2019 Actual Paper Slot 1
Question Numbers (43 to 46): Answer the questions on the basis of the information given below.

A new game show on TV has 100 boxes numbered 1, 2, . . . , 100 in a row, each containing a mystery prize. The prizes are items of different types, a, b, c, . . . , in decreasing order of value. The most expensive item is of type a, a diamond ring, and there is exactly one of these. You are told that the number of items at least doubles as you move to the next type. For example, there would be at least twice as many items of type b as of type a, at least twice as many items of type c as of type b and so on. There is no particular order in which the prizes are placed in the boxes.

You ask for the type of item in box 45. Instead of being given a direct answer, you are told that there are 31 items of the same type as box 45 in boxes 1 to 44 and 43 items of the same type as box 45 in boxes 46 to 100.

What is the maximum possible number of different types of items?

A
5
B
4
C
3
D
6
Solution:
The total number of items from 1 to 100, which are of same type as in box 45 = 31 + 1 + 43 = 75
Now to maximize the number of items, a = 1, b = 2, c = 4, d = 18 and e = 75(given) There can be maximum 5 types of items.
If we consider number of items to be 6, then minimum number of items of 5th type will be 16,
1 + 2 + 4 + 8 + 16 + 75 = 106 which is more than 100.
Solution:


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Solution:


Solution:


Solution:


Solution:
Congress – Thursday              BJP – Friday
SP – Thursday                    BSP – Friday
CPM – Friday
Congress procession can only be allowed on Thursday.


Solution:
Congress – Thursday              BJP – Friday
SP – Thursday                    BSP – Friday
CPM – Friday
According to the given table, statement (4) is not true.


Solution:
It is given that the most expensive item is a diamond ring of type a and there is exactly one of these. Since the item b should be at least twice. The minimum number of items will be obtained when a = 1 and b = 99, which means there are only two different types of items.


Solution:
It is given that the most expensive item is a diamond ring of type a and there is exactly one of these. Since the number of items of type b should be at least twice of that of a and the number of items of type c should be at least twice of that of b and so on. So the maximum number of different types of items of a, b and c will be obtained when a = 1, b = 2, c = 4, d = 8, e = 16, f = 69. Hence the maximum number of different types of items will be 6.
If the number of items is 7, then the minimum number of prizes should be 1 + 2 + 4 + 8 + 16 + 32 + 64 = 127 which is more than 100. Hence, 6 is the answer.


Solution:
Option 1: There are exactly 75 items of type e.
a = 1, b = 2, c = 4, d = 8, e = 85. Here the maximum value of e = 85. Hence it can take the value 75.
An example of such case is a = 1, b = 2, c = 4, d = 18, e = 75
Option 2: There are exactly 45 items of type c.
Since the value of d should be at least 90, it means that d is not present because 45 + 90 will be more than 100(maximum number of items). Only a, b and c are present.
The maximum value of b = 22 and a = 1,
but 45 + 22 + 1 = 68, which is less than 100. So this case is not possible.
Option 3: There are exactly 30 items of type b. a = 1, b = 30 and c = 69. Hence this case is also possible.
Option 4: There are exactly 60 items of type d. d = 60, c = 30, b = 9 and a = 1. a + b + c + d = 100. Hence, this case is possible.
2 is the answer.


Solution:
The total number of items from 1 to 100, which are of same type as in box 45 = 31 + 1 + 43 = 75
Now to maximize the number of items, a = 1, b = 2, c = 4, d = 18 and e = 75(given) There can be maximum 5 types of items.
If we consider number of items to be 6, then minimum number of items of 5th type will be 16,
1 + 2 + 4 + 8 + 16 + 75 = 106 which is more than 100.


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