Let a, b, m and n be natural numbers such that a > 1 and b > 1. If am bn = 144145, then the largest possible value of n – m is
Let n and m be two positive integers such that there are exactly 41 integers greater than 8m and less than 8n, which can be expressed as powers of 2. Then, the smallest possible value of n + m is
Let n be any natural number such that 5n – 1 < 3n + 1. Then, the least integer value of m that satisfies 3n + 1 < 2n + m for each such n, is