Case let
Q.No: 1
Test Name : CAT 2019 Actual Paper Slot 2
Question Numbers (59 to 62): Answer the questions
on the basis of the information given below.
Students in a college are discussing two proposals --
A: a proposal by the authorities to introduce dress code on campus, and
B: a proposal by the students to allow multinational food franchises to set up outlets on college campus.
A student does not necessarily support either of the two proposals.
In an upcoming election for student union president, there are two candidates in fray: Sunita and Ragini. Every student prefers one of the two candidates.
A survey was conducted among the students by picking a sample of 500 students. The following information was noted from this survey.
1. 250 students supported proposal A and 250 students supported proposal B.
2. Among the 200 students who preferred Sunita as student union president, 80% supported proposal A.
3. Among those who preferred Ragini, 30% supported proposal A.
4. 20% of those who supported proposal B preferred Sunita.
5. 40% of those who did not support proposal B preferred Ragini.
6. Every student who preferred Sunita and supported proposal B also supported proposal A.
7. Among those who preferred Ragini, 20% did not support any of the proposals.
Students in a college are discussing two proposals --
A: a proposal by the authorities to introduce dress code on campus, and
B: a proposal by the students to allow multinational food franchises to set up outlets on college campus.
A student does not necessarily support either of the two proposals.
In an upcoming election for student union president, there are two candidates in fray: Sunita and Ragini. Every student prefers one of the two candidates.
A survey was conducted among the students by picking a sample of 500 students. The following information was noted from this survey.
1. 250 students supported proposal A and 250 students supported proposal B.
2. Among the 200 students who preferred Sunita as student union president, 80% supported proposal A.
3. Among those who preferred Ragini, 30% supported proposal A.
4. 20% of those who supported proposal B preferred Sunita.
5. 40% of those who did not support proposal B preferred Ragini.
6. Every student who preferred Sunita and supported proposal B also supported proposal A.
7. Among those who preferred Ragini, 20% did not support any of the proposals.
Among the students surveyed who supported proposal A, what percentage preferred Sunita for student union president?
Solution:
Q.No: 2
Test Name : CAT 2019 Actual Paper Slot 2
Question Numbers (59 to 62): Answer the questions
on the basis of the information given below.
Students in a college are discussing two proposals --
A: a proposal by the authorities to introduce dress code on campus, and
B: a proposal by the students to allow multinational food franchises to set up outlets on college campus.
A student does not necessarily support either of the two proposals.
In an upcoming election for student union president, there are two candidates in fray: Sunita and Ragini. Every student prefers one of the two candidates.
A survey was conducted among the students by picking a sample of 500 students. The following information was noted from this survey.
1. 250 students supported proposal A and 250 students supported proposal B.
2. Among the 200 students who preferred Sunita as student union president, 80% supported proposal A.
3. Among those who preferred Ragini, 30% supported proposal A.
4. 20% of those who supported proposal B preferred Sunita.
5. 40% of those who did not support proposal B preferred Ragini.
6. Every student who preferred Sunita and supported proposal B also supported proposal A.
7. Among those who preferred Ragini, 20% did not support any of the proposals.
Students in a college are discussing two proposals --
A: a proposal by the authorities to introduce dress code on campus, and
B: a proposal by the students to allow multinational food franchises to set up outlets on college campus.
A student does not necessarily support either of the two proposals.
In an upcoming election for student union president, there are two candidates in fray: Sunita and Ragini. Every student prefers one of the two candidates.
A survey was conducted among the students by picking a sample of 500 students. The following information was noted from this survey.
1. 250 students supported proposal A and 250 students supported proposal B.
2. Among the 200 students who preferred Sunita as student union president, 80% supported proposal A.
3. Among those who preferred Ragini, 30% supported proposal A.
4. 20% of those who supported proposal B preferred Sunita.
5. 40% of those who did not support proposal B preferred Ragini.
6. Every student who preferred Sunita and supported proposal B also supported proposal A.
7. Among those who preferred Ragini, 20% did not support any of the proposals.
What percentage of the students surveyed who did not support proposal A preferred Ragini as student union president?
Solution:
Q.No: 3
Test Name : CAT 2019 Actual Paper Slot 2
Question Numbers (59 to 62): Answer the questions
on the basis of the information given below.
Students in a college are discussing two proposals --
A: a proposal by the authorities to introduce dress code on campus, and
B: a proposal by the students to allow multinational food franchises to set up outlets on college campus.
A student does not necessarily support either of the two proposals.
In an upcoming election for student union president, there are two candidates in fray: Sunita and Ragini. Every student prefers one of the two candidates.
A survey was conducted among the students by picking a sample of 500 students. The following information was noted from this survey.
1. 250 students supported proposal A and 250 students supported proposal B.
2. Among the 200 students who preferred Sunita as student union president, 80% supported proposal A.
3. Among those who preferred Ragini, 30% supported proposal A.
4. 20% of those who supported proposal B preferred Sunita.
5. 40% of those who did not support proposal B preferred Ragini.
6. Every student who preferred Sunita and supported proposal B also supported proposal A.
7. Among those who preferred Ragini, 20% did not support any of the proposals.
Students in a college are discussing two proposals --
A: a proposal by the authorities to introduce dress code on campus, and
B: a proposal by the students to allow multinational food franchises to set up outlets on college campus.
A student does not necessarily support either of the two proposals.
In an upcoming election for student union president, there are two candidates in fray: Sunita and Ragini. Every student prefers one of the two candidates.
A survey was conducted among the students by picking a sample of 500 students. The following information was noted from this survey.
1. 250 students supported proposal A and 250 students supported proposal B.
2. Among the 200 students who preferred Sunita as student union president, 80% supported proposal A.
3. Among those who preferred Ragini, 30% supported proposal A.
4. 20% of those who supported proposal B preferred Sunita.
5. 40% of those who did not support proposal B preferred Ragini.
6. Every student who preferred Sunita and supported proposal B also supported proposal A.
7. Among those who preferred Ragini, 20% did not support any of the proposals.
What percentage of the students surveyed who supported both proposals A and B preferred Sunita as student union president?
Solution:
Q.No: 4
Test Name : CAT 2019 Actual Paper Slot 2
Question Numbers (59 to 62): Answer the questions
on the basis of the information given below.
Students in a college are discussing two proposals --
A: a proposal by the authorities to introduce dress code on campus, and
B: a proposal by the students to allow multinational food franchises to set up outlets on college campus.
A student does not necessarily support either of the two proposals.
In an upcoming election for student union president, there are two candidates in fray: Sunita and Ragini. Every student prefers one of the two candidates.
A survey was conducted among the students by picking a sample of 500 students. The following information was noted from this survey.
1. 250 students supported proposal A and 250 students supported proposal B.
2. Among the 200 students who preferred Sunita as student union president, 80% supported proposal A.
3. Among those who preferred Ragini, 30% supported proposal A.
4. 20% of those who supported proposal B preferred Sunita.
5. 40% of those who did not support proposal B preferred Ragini.
6. Every student who preferred Sunita and supported proposal B also supported proposal A.
7. Among those who preferred Ragini, 20% did not support any of the proposals.
Students in a college are discussing two proposals --
A: a proposal by the authorities to introduce dress code on campus, and
B: a proposal by the students to allow multinational food franchises to set up outlets on college campus.
A student does not necessarily support either of the two proposals.
In an upcoming election for student union president, there are two candidates in fray: Sunita and Ragini. Every student prefers one of the two candidates.
A survey was conducted among the students by picking a sample of 500 students. The following information was noted from this survey.
1. 250 students supported proposal A and 250 students supported proposal B.
2. Among the 200 students who preferred Sunita as student union president, 80% supported proposal A.
3. Among those who preferred Ragini, 30% supported proposal A.
4. 20% of those who supported proposal B preferred Sunita.
5. 40% of those who did not support proposal B preferred Ragini.
6. Every student who preferred Sunita and supported proposal B also supported proposal A.
7. Among those who preferred Ragini, 20% did not support any of the proposals.
How many of the students surveyed supported proposal B, did not support proposal A and preferred Ragini as student union president?
Solution:
Q.No: 5
Test Name : CAT Actual Paper 2021 Slot-3
Comprehension:
Each of the bottles mentioned in this question contains 50 ml of liquid. The liquid in any bottle can be 100% pure content (P) or can have certain amount of impurity (I). Visually it is not possible to distinguish between P and I. There is a testing device which detects impurity, as long as the percentage of impurity in the content tested is 10% or more.
For example, suppose bottle 1 contains only P, and bottle 2 contains 80% P and 20% I. If content from bottle 1 is tested, it will be found out that it contains only P. If content of bottle 2 is tested, the test will reveal that it contains some amount of I. If 10 ml of content from bottle 1 is mixed with 20 ml content from bottle 2, the test will show that the mixture has impurity, and hence we can conclude that at least one of the two bottles has I. However, if 10 ml of content from bottle 1 is mixed with 5 ml of content from bottle 2. the test will not detect any impurity in the resultant mixture.
Each of the bottles mentioned in this question contains 50 ml of liquid. The liquid in any bottle can be 100% pure content (P) or can have certain amount of impurity (I). Visually it is not possible to distinguish between P and I. There is a testing device which detects impurity, as long as the percentage of impurity in the content tested is 10% or more.
For example, suppose bottle 1 contains only P, and bottle 2 contains 80% P and 20% I. If content from bottle 1 is tested, it will be found out that it contains only P. If content of bottle 2 is tested, the test will reveal that it contains some amount of I. If 10 ml of content from bottle 1 is mixed with 20 ml content from bottle 2, the test will show that the mixture has impurity, and hence we can conclude that at least one of the two bottles has I. However, if 10 ml of content from bottle 1 is mixed with 5 ml of content from bottle 2. the test will not detect any impurity in the resultant mixture.
5 ml of content from bottle A is mixed with 5 ml of content from bottle B. The resultant mixture, when tested, detects the presence of I. If it is known that bottle A contains only P, what BEST can be concluded about the volume of I in bottle B?
Solution:
Q.No: 6
Test Name : CAT Actual Paper 2021 Slot-3
Comprehension:
Each of the bottles mentioned in this question contains 50 ml of liquid. The liquid in any bottle can be 100% pure content (P) or can have certain amount of impurity (I). Visually it is not possible to distinguish between P and I. There is a testing device which detects impurity, as long as the percentage of impurity in the content tested is 10% or more.
For example, suppose bottle 1 contains only P, and bottle 2 contains 80% P and 20% I. If content from bottle 1 is tested, it will be found out that it contains only P. If content of bottle 2 is tested, the test will reveal that it contains some amount of I. If 10 ml of content from bottle 1 is mixed with 20 ml content from bottle 2, the test will show that the mixture has impurity, and hence we can conclude that at least one of the two bottles has I. However, if 10 ml of content from bottle 1 is mixed with 5 ml of content from bottle 2. the test will not detect any impurity in the resultant mixture.
Each of the bottles mentioned in this question contains 50 ml of liquid. The liquid in any bottle can be 100% pure content (P) or can have certain amount of impurity (I). Visually it is not possible to distinguish between P and I. There is a testing device which detects impurity, as long as the percentage of impurity in the content tested is 10% or more.
For example, suppose bottle 1 contains only P, and bottle 2 contains 80% P and 20% I. If content from bottle 1 is tested, it will be found out that it contains only P. If content of bottle 2 is tested, the test will reveal that it contains some amount of I. If 10 ml of content from bottle 1 is mixed with 20 ml content from bottle 2, the test will show that the mixture has impurity, and hence we can conclude that at least one of the two bottles has I. However, if 10 ml of content from bottle 1 is mixed with 5 ml of content from bottle 2. the test will not detect any impurity in the resultant mixture.
There are four bottles. Each bottle is known to contain only P or only I. They will be considered to be “collectively ready for despatch” if all of them contain only P. In minimum how many tests, is it possible to ascertain whether these four bottles are “collectively ready for despatch”?
Solution:
Q.No: 7
Test Name : CAT Actual Paper 2021 Slot-3
Comprehension:
Each of the bottles mentioned in this question contains 50 ml of liquid. The liquid in any bottle can be 100% pure content (P) or can have certain amount of impurity (I). Visually it is not possible to distinguish between P and I. There is a testing device which detects impurity, as long as the percentage of impurity in the content tested is 10% or more.
For example, suppose bottle 1 contains only P, and bottle 2 contains 80% P and 20% I. If content from bottle 1 is tested, it will be found out that it contains only P. If content of bottle 2 is tested, the test will reveal that it contains some amount of I. If 10 ml of content from bottle 1 is mixed with 20 ml content from bottle 2, the test will show that the mixture has impurity, and hence we can conclude that at least one of the two bottles has I. However, if 10 ml of content from bottle 1 is mixed with 5 ml of content from bottle 2. the test will not detect any impurity in the resultant mixture.
Each of the bottles mentioned in this question contains 50 ml of liquid. The liquid in any bottle can be 100% pure content (P) or can have certain amount of impurity (I). Visually it is not possible to distinguish between P and I. There is a testing device which detects impurity, as long as the percentage of impurity in the content tested is 10% or more.
For example, suppose bottle 1 contains only P, and bottle 2 contains 80% P and 20% I. If content from bottle 1 is tested, it will be found out that it contains only P. If content of bottle 2 is tested, the test will reveal that it contains some amount of I. If 10 ml of content from bottle 1 is mixed with 20 ml content from bottle 2, the test will show that the mixture has impurity, and hence we can conclude that at least one of the two bottles has I. However, if 10 ml of content from bottle 1 is mixed with 5 ml of content from bottle 2. the test will not detect any impurity in the resultant mixture.
There are four bottles. It is known that three of these bottles contain only P, while the remaining one contains 80% P and 20% I. What is the minimum number of tests required to definitely identify the bottle containing some amount of I?
Solution:
Q.No: 8
Test Name : CAT Actual Paper 2021 Slot-3
Comprehension:
Each of the bottles mentioned in this question contains 50 ml of liquid. The liquid in any bottle can be 100% pure content (P) or can have certain amount of impurity (I). Visually it is not possible to distinguish between P and I. There is a testing device which detects impurity, as long as the percentage of impurity in the content tested is 10% or more.
For example, suppose bottle 1 contains only P, and bottle 2 contains 80% P and 20% I. If content from bottle 1 is tested, it will be found out that it contains only P. If content of bottle 2 is tested, the test will reveal that it contains some amount of I. If 10 ml of content from bottle 1 is mixed with 20 ml content from bottle 2, the test will show that the mixture has impurity, and hence we can conclude that at least one of the two bottles has I. However, if 10 ml of content from bottle 1 is mixed with 5 ml of content from bottle 2. the test will not detect any impurity in the resultant mixture.
Each of the bottles mentioned in this question contains 50 ml of liquid. The liquid in any bottle can be 100% pure content (P) or can have certain amount of impurity (I). Visually it is not possible to distinguish between P and I. There is a testing device which detects impurity, as long as the percentage of impurity in the content tested is 10% or more.
For example, suppose bottle 1 contains only P, and bottle 2 contains 80% P and 20% I. If content from bottle 1 is tested, it will be found out that it contains only P. If content of bottle 2 is tested, the test will reveal that it contains some amount of I. If 10 ml of content from bottle 1 is mixed with 20 ml content from bottle 2, the test will show that the mixture has impurity, and hence we can conclude that at least one of the two bottles has I. However, if 10 ml of content from bottle 1 is mixed with 5 ml of content from bottle 2. the test will not detect any impurity in the resultant mixture.
There are four bottles. It is known that either one or two of these bottles contain(s) only P, while the remaining ones contain 85% P and 15% I. What is the minimum number of tests required to ascertain the exact number of bottles containing only P?
Solution:
Q.No: 9
Test Name : CAT Actual Paper 2022 Slot-2
Question Numbers (35 to 39): A few salesmen are
employed to sell a product called TRICCEK among
households in various housing complexes. On each
day, a salesman is assigned to visit one housing
complex. Once a salesman enters a housing complex,
he can meet any number of households in the time
available. However, if a household makes a complaint
against the salesman, then he must leave the housing
complex immediately and cannot meet any other
household on that day. A household may buy any
number of TRICCEK items or may not buy any item.
The salesman needs to record the total number of
TRICCEK items sold as well as the number of
households met in each day. The success rate of a
salesman for a day is defined as the ratio of the number
of items sold to the number of households met on that
day. Some details about the performances of three
salesmen - Tohri, Hokli and Lahur, on two particular
days are given below.
1. Over the two days, all three of them met the same total number of households, and each of them sold a total of 100 items.
2. On both days, Lahur met the same number of households and sold the same number of items.
3. Hokli could not sell any item on the second day because the first household he met on that day complained against him.
4. Tohri met 30 more households on the second day than on the first day.
5. Tohri’s success rate was twice that of Lahur’s on the first day, and it was 75% of Lahur’s on the second day.
1. Over the two days, all three of them met the same total number of households, and each of them sold a total of 100 items.
2. On both days, Lahur met the same number of households and sold the same number of items.
3. Hokli could not sell any item on the second day because the first household he met on that day complained against him.
4. Tohri met 30 more households on the second day than on the first day.
5. Tohri’s success rate was twice that of Lahur’s on the first day, and it was 75% of Lahur’s on the second day.
What was the total number of households met by Tohri, Hokli and Lahur on the first day?
Solution:
Total number of households met by Tohri, Hokli and Lahur on day 1 = 10 + 49 + 25 = 84.
Total number of households met by Tohri, Hokli and Lahur on day 1 = 10 + 49 + 25 = 84.
Q.No: 10
Test Name : CAT Actual Paper 2022 Slot-2
Question Numbers (35 to 39): A few salesmen are
employed to sell a product called TRICCEK among
households in various housing complexes. On each
day, a salesman is assigned to visit one housing
complex. Once a salesman enters a housing complex,
he can meet any number of households in the time
available. However, if a household makes a complaint
against the salesman, then he must leave the housing
complex immediately and cannot meet any other
household on that day. A household may buy any
number of TRICCEK items or may not buy any item.
The salesman needs to record the total number of
TRICCEK items sold as well as the number of
households met in each day. The success rate of a
salesman for a day is defined as the ratio of the number
of items sold to the number of households met on that
day. Some details about the performances of three
salesmen - Tohri, Hokli and Lahur, on two particular
days are given below.
1. Over the two days, all three of them met the same total number of households, and each of them sold a total of 100 items.
2. On both days, Lahur met the same number of households and sold the same number of items.
3. Hokli could not sell any item on the second day because the first household he met on that day complained against him.
4. Tohri met 30 more households on the second day than on the first day.
5. Tohri’s success rate was twice that of Lahur’s on the first day, and it was 75% of Lahur’s on the second day.
1. Over the two days, all three of them met the same total number of households, and each of them sold a total of 100 items.
2. On both days, Lahur met the same number of households and sold the same number of items.
3. Hokli could not sell any item on the second day because the first household he met on that day complained against him.
4. Tohri met 30 more households on the second day than on the first day.
5. Tohri’s success rate was twice that of Lahur’s on the first day, and it was 75% of Lahur’s on the second day.
How many TRICCEK items were sold by Tohri on the first day?
Solution:
Total items sold by Tohri on day 1 = 40.
Total items sold by Tohri on day 1 = 40.
Q.No: 11
Test Name : CAT Actual Paper 2022 Slot-2
Question Numbers (35 to 39): A few salesmen are
employed to sell a product called TRICCEK among
households in various housing complexes. On each
day, a salesman is assigned to visit one housing
complex. Once a salesman enters a housing complex,
he can meet any number of households in the time
available. However, if a household makes a complaint
against the salesman, then he must leave the housing
complex immediately and cannot meet any other
household on that day. A household may buy any
number of TRICCEK items or may not buy any item.
The salesman needs to record the total number of
TRICCEK items sold as well as the number of
households met in each day. The success rate of a
salesman for a day is defined as the ratio of the number
of items sold to the number of households met on that
day. Some details about the performances of three
salesmen - Tohri, Hokli and Lahur, on two particular
days are given below.
1. Over the two days, all three of them met the same total number of households, and each of them sold a total of 100 items.
2. On both days, Lahur met the same number of households and sold the same number of items.
3. Hokli could not sell any item on the second day because the first household he met on that day complained against him.
4. Tohri met 30 more households on the second day than on the first day.
5. Tohri’s success rate was twice that of Lahur’s on the first day, and it was 75% of Lahur’s on the second day.
1. Over the two days, all three of them met the same total number of households, and each of them sold a total of 100 items.
2. On both days, Lahur met the same number of households and sold the same number of items.
3. Hokli could not sell any item on the second day because the first household he met on that day complained against him.
4. Tohri met 30 more households on the second day than on the first day.
5. Tohri’s success rate was twice that of Lahur’s on the first day, and it was 75% of Lahur’s on the second day.
How many households did Lahur meet on the second day?
Solution:
Number of households visited by Lahur on day 2 = 25, which lies between 21 and 29.
Number of households visited by Lahur on day 2 = 25, which lies between 21 and 29.
Q.No: 12
Test Name : CAT Actual Paper 2022 Slot-2
Question Numbers (35 to 39): A few salesmen are
employed to sell a product called TRICCEK among
households in various housing complexes. On each
day, a salesman is assigned to visit one housing
complex. Once a salesman enters a housing complex,
he can meet any number of households in the time
available. However, if a household makes a complaint
against the salesman, then he must leave the housing
complex immediately and cannot meet any other
household on that day. A household may buy any
number of TRICCEK items or may not buy any item.
The salesman needs to record the total number of
TRICCEK items sold as well as the number of
households met in each day. The success rate of a
salesman for a day is defined as the ratio of the number
of items sold to the number of households met on that
day. Some details about the performances of three
salesmen - Tohri, Hokli and Lahur, on two particular
days are given below.
1. Over the two days, all three of them met the same total number of households, and each of them sold a total of 100 items.
2. On both days, Lahur met the same number of households and sold the same number of items.
3. Hokli could not sell any item on the second day because the first household he met on that day complained against him.
4. Tohri met 30 more households on the second day than on the first day.
5. Tohri’s success rate was twice that of Lahur’s on the first day, and it was 75% of Lahur’s on the second day.
1. Over the two days, all three of them met the same total number of households, and each of them sold a total of 100 items.
2. On both days, Lahur met the same number of households and sold the same number of items.
3. Hokli could not sell any item on the second day because the first household he met on that day complained against him.
4. Tohri met 30 more households on the second day than on the first day.
5. Tohri’s success rate was twice that of Lahur’s on the first day, and it was 75% of Lahur’s on the second day.
How many households did Tohri meet on the first day?
Solution:
Tohri visited 10 households on day 1.
Tohri visited 10 households on day 1.
Q.No: 13
Test Name : CAT Actual Paper 2022 Slot-2
Question Numbers (35 to 39): A few salesmen are
employed to sell a product called TRICCEK among
households in various housing complexes. On each
day, a salesman is assigned to visit one housing
complex. Once a salesman enters a housing complex,
he can meet any number of households in the time
available. However, if a household makes a complaint
against the salesman, then he must leave the housing
complex immediately and cannot meet any other
household on that day. A household may buy any
number of TRICCEK items or may not buy any item.
The salesman needs to record the total number of
TRICCEK items sold as well as the number of
households met in each day. The success rate of a
salesman for a day is defined as the ratio of the number
of items sold to the number of households met on that
day. Some details about the performances of three
salesmen - Tohri, Hokli and Lahur, on two particular
days are given below.
1. Over the two days, all three of them met the same total number of households, and each of them sold a total of 100 items.
2. On both days, Lahur met the same number of households and sold the same number of items.
3. Hokli could not sell any item on the second day because the first household he met on that day complained against him.
4. Tohri met 30 more households on the second day than on the first day.
5. Tohri’s success rate was twice that of Lahur’s on the first day, and it was 75% of Lahur’s on the second day.
1. Over the two days, all three of them met the same total number of households, and each of them sold a total of 100 items.
2. On both days, Lahur met the same number of households and sold the same number of items.
3. Hokli could not sell any item on the second day because the first household he met on that day complained against him.
4. Tohri met 30 more households on the second day than on the first day.
5. Tohri’s success rate was twice that of Lahur’s on the first day, and it was 75% of Lahur’s on the second day.
Which of the following statements is FALSE?
Solution:
Let us go by options (observe the success rates in the above table):
(1) Tohri had a higher success rate on the first day compared to the second day. This is true.
(2) Among the three, Tohri had the highest success rate on the second day. This is false.
(3) Among the three, Lahur had the lowest success rate on the first day. This is true.
(4) Among the three, Tohri had the highest success rate on the first day. This is true.
Let us go by options (observe the success rates in the above table):
(1) Tohri had a higher success rate on the first day compared to the second day. This is true.
(2) Among the three, Tohri had the highest success rate on the second day. This is false.
(3) Among the three, Lahur had the lowest success rate on the first day. This is true.
(4) Among the three, Tohri had the highest success rate on the first day. This is true.
Q.No: 14
Test Name : CAT Actual Paper 2022 Slot-3
Directions for question (25 to 29): All the first-year students
in the computer science (CS) department in a university
take both the courses (i) AI and (ii) ML. Students from
other departments (non-CS students) can also take one
of these two courses, but not both. Students who fail in
a course get an F grade; others pass and are awarded
A or B or C grades depending on their performance. The
following are some additional facts about the number of
students who took these two courses this year and the
grades they obtained.
1. The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.
2. The number of non-CS students who took either AI or ML was equal to the number of CS students.
3. The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.
4. In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.
5. No CS student failed in AI, while no non-CS student got an A grade in AI.
6. The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.
7. The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 : 1.
8. 30 students failed in ML.
1. The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.
2. The number of non-CS students who took either AI or ML was equal to the number of CS students.
3. The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.
4. In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.
5. No CS student failed in AI, while no non-CS student got an A grade in AI.
6. The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.
7. The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 : 1.
8. 30 students failed in ML.
How many students took AI?
Solution:
Number of students took AI = 210 + 60 = 270.
Number of students took AI = 210 + 60 = 270.
Q.No: 15
Test Name : CAT Actual Paper 2022 Slot-3
Directions for question (25 to 29): All the first-year students
in the computer science (CS) department in a university
take both the courses (i) AI and (ii) ML. Students from
other departments (non-CS students) can also take one
of these two courses, but not both. Students who fail in
a course get an F grade; others pass and are awarded
A or B or C grades depending on their performance. The
following are some additional facts about the number of
students who took these two courses this year and the
grades they obtained.
1. The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.
2. The number of non-CS students who took either AI or ML was equal to the number of CS students.
3. The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.
4. In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.
5. No CS student failed in AI, while no non-CS student got an A grade in AI.
6. The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.
7. The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 : 1.
8. 30 students failed in ML.
1. The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.
2. The number of non-CS students who took either AI or ML was equal to the number of CS students.
3. The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.
4. In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.
5. No CS student failed in AI, while no non-CS student got an A grade in AI.
6. The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.
7. The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 : 1.
8. 30 students failed in ML.
How many CS students failed in ML?
Solution:
Number of CS students failed in ML is 12.
Number of CS students failed in ML is 12.
Q.No: 16
Test Name : CAT Actual Paper 2022 Slot-3
Directions for question (25 to 29): All the first-year students
in the computer science (CS) department in a university
take both the courses (i) AI and (ii) ML. Students from
other departments (non-CS students) can also take one
of these two courses, but not both. Students who fail in
a course get an F grade; others pass and are awarded
A or B or C grades depending on their performance. The
following are some additional facts about the number of
students who took these two courses this year and the
grades they obtained.
1. The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.
2. The number of non-CS students who took either AI or ML was equal to the number of CS students.
3. The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.
4. In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.
5. No CS student failed in AI, while no non-CS student got an A grade in AI.
6. The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.
7. The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 : 1.
8. 30 students failed in ML.
1. The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.
2. The number of non-CS students who took either AI or ML was equal to the number of CS students.
3. The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.
4. In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.
5. No CS student failed in AI, while no non-CS student got an A grade in AI.
6. The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.
7. The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 : 1.
8. 30 students failed in ML.
How many non-CS students got A grade in ML?
Solution:
Number of non-CS students got A grade in ML is 27.
Number of non-CS students got A grade in ML is 27.
Q.No: 17
Test Name : CAT Actual Paper 2022 Slot-3
Directions for question (25 to 29): All the first-year students
in the computer science (CS) department in a university
take both the courses (i) AI and (ii) ML. Students from
other departments (non-CS students) can also take one
of these two courses, but not both. Students who fail in
a course get an F grade; others pass and are awarded
A or B or C grades depending on their performance. The
following are some additional facts about the number of
students who took these two courses this year and the
grades they obtained.
1. The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.
2. The number of non-CS students who took either AI or ML was equal to the number of CS students.
3. The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.
4. In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.
5. No CS student failed in AI, while no non-CS student got an A grade in AI.
6. The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.
7. The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 : 1.
8. 30 students failed in ML.
1. The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.
2. The number of non-CS students who took either AI or ML was equal to the number of CS students.
3. The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.
4. In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.
5. No CS student failed in AI, while no non-CS student got an A grade in AI.
6. The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.
7. The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 : 1.
8. 30 students failed in ML.
How many students got A grade in AI?
Solution:
Number of students got A grade in AI is 63 + 0 = 63.
Number of students got A grade in AI is 63 + 0 = 63.
Q.No: 18
Test Name : CAT Actual Paper 2022 Slot-3
Directions for question (25 to 29): All the first-year students
in the computer science (CS) department in a university
take both the courses (i) AI and (ii) ML. Students from
other departments (non-CS students) can also take one
of these two courses, but not both. Students who fail in
a course get an F grade; others pass and are awarded
A or B or C grades depending on their performance. The
following are some additional facts about the number of
students who took these two courses this year and the
grades they obtained.
1. The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.
2. The number of non-CS students who took either AI or ML was equal to the number of CS students.
3. The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.
4. In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.
5. No CS student failed in AI, while no non-CS student got an A grade in AI.
6. The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.
7. The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 : 1.
8. 30 students failed in ML.
1. The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.
2. The number of non-CS students who took either AI or ML was equal to the number of CS students.
3. The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.
4. In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.
5. No CS student failed in AI, while no non-CS student got an A grade in AI.
6. The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.
7. The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 : 1.
8. 30 students failed in ML.
How many non-CS students got B grade in ML?
Solution:
Number of non-CS students got B grade in ML is 75.
Number of non-CS students got B grade in ML is 75.
Q.No: 19
Test Name : CAT Actual Paper 2023 Slot 3
Question Numbers (25 to 29): An air conditioner (AC)
company has four dealers – D1, D2, D3 and D4 in a city.
It is evaluating sales performances of these dealers. The
company sells two variants of ACs – Window and Split.
Both these variants can be either Inverter type or Noninverter
type. It is known that of the total number of ACs
sold in the city, 25% were of Window variant, while the
rest were of Split variant. Among the Inverter ACs sold,
20% were of Window variant.
The following information is also known:
1. Every dealer sold at least two window ACs.
2. D1 sold 13 inverter ACs, while D3 sold 5 Non-inverter ACs.
3. A total of six Window Non-inverter ACs and 36 Split Inverter ACs were sold in the city.
4. The number of Split ACs sold by D1 was twice the number of Window ACs sold by it.
5. D3 and D4 sold an equal number of Window ACs and this number was one-third of the number of similar ACs sold by D2.
6. D2 and D3 were the only ones who sold Window Non-inverter ACs. The number of these ACs sold by D2 was twice the number of these ACs sold by D3.
7. D3 and D4 sold an equal number of Split Inverter ACs. This number was half the number of similar ACs sold by D2.
The following information is also known:
1. Every dealer sold at least two window ACs.
2. D1 sold 13 inverter ACs, while D3 sold 5 Non-inverter ACs.
3. A total of six Window Non-inverter ACs and 36 Split Inverter ACs were sold in the city.
4. The number of Split ACs sold by D1 was twice the number of Window ACs sold by it.
5. D3 and D4 sold an equal number of Window ACs and this number was one-third of the number of similar ACs sold by D2.
6. D2 and D3 were the only ones who sold Window Non-inverter ACs. The number of these ACs sold by D2 was twice the number of these ACs sold by D3.
7. D3 and D4 sold an equal number of Split Inverter ACs. This number was half the number of similar ACs sold by D2.
Which of the following statements is necessarily false?
Solution:
D1 and D3 together sold 27 ACs whereas D2 and D4 sold 33 ACs. Hence, option (1) is necessarily false.
All the other statements are not necessarily false.
Hence, the correct answer is option (1).
D1 and D3 together sold 27 ACs whereas D2 and D4 sold 33 ACs. Hence, option (1) is necessarily false.
All the other statements are not necessarily false.
Hence, the correct answer is option (1).
Q.No: 20
Test Name : CAT Actual Paper 2023 Slot 3
Question Numbers (25 to 29): An air conditioner (AC)
company has four dealers – D1, D2, D3 and D4 in a city.
It is evaluating sales performances of these dealers. The
company sells two variants of ACs – Window and Split.
Both these variants can be either Inverter type or Noninverter
type. It is known that of the total number of ACs
sold in the city, 25% were of Window variant, while the
rest were of Split variant. Among the Inverter ACs sold,
20% were of Window variant.
The following information is also known:
1. Every dealer sold at least two window ACs.
2. D1 sold 13 inverter ACs, while D3 sold 5 Non-inverter ACs.
3. A total of six Window Non-inverter ACs and 36 Split Inverter ACs were sold in the city.
4. The number of Split ACs sold by D1 was twice the number of Window ACs sold by it.
5. D3 and D4 sold an equal number of Window ACs and this number was one-third of the number of similar ACs sold by D2.
6. D2 and D3 were the only ones who sold Window Non-inverter ACs. The number of these ACs sold by D2 was twice the number of these ACs sold by D3.
7. D3 and D4 sold an equal number of Split Inverter ACs. This number was half the number of similar ACs sold by D2.
The following information is also known:
1. Every dealer sold at least two window ACs.
2. D1 sold 13 inverter ACs, while D3 sold 5 Non-inverter ACs.
3. A total of six Window Non-inverter ACs and 36 Split Inverter ACs were sold in the city.
4. The number of Split ACs sold by D1 was twice the number of Window ACs sold by it.
5. D3 and D4 sold an equal number of Window ACs and this number was one-third of the number of similar ACs sold by D2.
6. D2 and D3 were the only ones who sold Window Non-inverter ACs. The number of these ACs sold by D2 was twice the number of these ACs sold by D3.
7. D3 and D4 sold an equal number of Split Inverter ACs. This number was half the number of similar ACs sold by D2.
How many Split Inverter ACs did D2 sell?
Solution:
Total number of Split Inverter ACs sold by D2 = 14
Total number of Split Inverter ACs sold by D2 = 14
Q.No: 21
Test Name : CAT Actual Paper 2023 Slot 3
Question Numbers (25 to 29): An air conditioner (AC)
company has four dealers – D1, D2, D3 and D4 in a city.
It is evaluating sales performances of these dealers. The
company sells two variants of ACs – Window and Split.
Both these variants can be either Inverter type or Noninverter
type. It is known that of the total number of ACs
sold in the city, 25% were of Window variant, while the
rest were of Split variant. Among the Inverter ACs sold,
20% were of Window variant.
The following information is also known:
1. Every dealer sold at least two window ACs.
2. D1 sold 13 inverter ACs, while D3 sold 5 Non-inverter ACs.
3. A total of six Window Non-inverter ACs and 36 Split Inverter ACs were sold in the city.
4. The number of Split ACs sold by D1 was twice the number of Window ACs sold by it.
5. D3 and D4 sold an equal number of Window ACs and this number was one-third of the number of similar ACs sold by D2.
6. D2 and D3 were the only ones who sold Window Non-inverter ACs. The number of these ACs sold by D2 was twice the number of these ACs sold by D3.
7. D3 and D4 sold an equal number of Split Inverter ACs. This number was half the number of similar ACs sold by D2.
The following information is also known:
1. Every dealer sold at least two window ACs.
2. D1 sold 13 inverter ACs, while D3 sold 5 Non-inverter ACs.
3. A total of six Window Non-inverter ACs and 36 Split Inverter ACs were sold in the city.
4. The number of Split ACs sold by D1 was twice the number of Window ACs sold by it.
5. D3 and D4 sold an equal number of Window ACs and this number was one-third of the number of similar ACs sold by D2.
6. D2 and D3 were the only ones who sold Window Non-inverter ACs. The number of these ACs sold by D2 was twice the number of these ACs sold by D3.
7. D3 and D4 sold an equal number of Split Inverter ACs. This number was half the number of similar ACs sold by D2.
What percentage of ACs sold were of Non-inverter type?
Solution:
Total number of ACs sold = 60; Total number of Non-inverter ACs sold = 15
Hence, required percentage = 15/60 x 100 = 25%.
Total number of ACs sold = 60; Total number of Non-inverter ACs sold = 15
Hence, required percentage = 15/60 x 100 = 25%.
Q.No: 22
Test Name : CAT Actual Paper 2023 Slot 3
Question Numbers (25 to 29): An air conditioner (AC)
company has four dealers – D1, D2, D3 and D4 in a city.
It is evaluating sales performances of these dealers. The
company sells two variants of ACs – Window and Split.
Both these variants can be either Inverter type or Noninverter
type. It is known that of the total number of ACs
sold in the city, 25% were of Window variant, while the
rest were of Split variant. Among the Inverter ACs sold,
20% were of Window variant.
The following information is also known:
1. Every dealer sold at least two window ACs.
2. D1 sold 13 inverter ACs, while D3 sold 5 Non-inverter ACs.
3. A total of six Window Non-inverter ACs and 36 Split Inverter ACs were sold in the city.
4. The number of Split ACs sold by D1 was twice the number of Window ACs sold by it.
5. D3 and D4 sold an equal number of Window ACs and this number was one-third of the number of similar ACs sold by D2.
6. D2 and D3 were the only ones who sold Window Non-inverter ACs. The number of these ACs sold by D2 was twice the number of these ACs sold by D3.
7. D3 and D4 sold an equal number of Split Inverter ACs. This number was half the number of similar ACs sold by D2.
The following information is also known:
1. Every dealer sold at least two window ACs.
2. D1 sold 13 inverter ACs, while D3 sold 5 Non-inverter ACs.
3. A total of six Window Non-inverter ACs and 36 Split Inverter ACs were sold in the city.
4. The number of Split ACs sold by D1 was twice the number of Window ACs sold by it.
5. D3 and D4 sold an equal number of Window ACs and this number was one-third of the number of similar ACs sold by D2.
6. D2 and D3 were the only ones who sold Window Non-inverter ACs. The number of these ACs sold by D2 was twice the number of these ACs sold by D3.
7. D3 and D4 sold an equal number of Split Inverter ACs. This number was half the number of similar ACs sold by D2.
What was the total number of ACs sold by D2 and D4?
Solution:
Total number of ACs sold by D2 and D4 = 60 – (15 + 12) = 33.
Total number of ACs sold by D2 and D4 = 60 – (15 + 12) = 33.
Q.No: 23
Test Name : CAT Actual Paper 2023 Slot 3
Question Numbers (25 to 29): An air conditioner (AC)
company has four dealers – D1, D2, D3 and D4 in a city.
It is evaluating sales performances of these dealers. The
company sells two variants of ACs – Window and Split.
Both these variants can be either Inverter type or Noninverter
type. It is known that of the total number of ACs
sold in the city, 25% were of Window variant, while the
rest were of Split variant. Among the Inverter ACs sold,
20% were of Window variant.
The following information is also known:
1. Every dealer sold at least two window ACs.
2. D1 sold 13 inverter ACs, while D3 sold 5 Non-inverter ACs.
3. A total of six Window Non-inverter ACs and 36 Split Inverter ACs were sold in the city.
4. The number of Split ACs sold by D1 was twice the number of Window ACs sold by it.
5. D3 and D4 sold an equal number of Window ACs and this number was one-third of the number of similar ACs sold by D2.
6. D2 and D3 were the only ones who sold Window Non-inverter ACs. The number of these ACs sold by D2 was twice the number of these ACs sold by D3.
7. D3 and D4 sold an equal number of Split Inverter ACs. This number was half the number of similar ACs sold by D2.
The following information is also known:
1. Every dealer sold at least two window ACs.
2. D1 sold 13 inverter ACs, while D3 sold 5 Non-inverter ACs.
3. A total of six Window Non-inverter ACs and 36 Split Inverter ACs were sold in the city.
4. The number of Split ACs sold by D1 was twice the number of Window ACs sold by it.
5. D3 and D4 sold an equal number of Window ACs and this number was one-third of the number of similar ACs sold by D2.
6. D2 and D3 were the only ones who sold Window Non-inverter ACs. The number of these ACs sold by D2 was twice the number of these ACs sold by D3.
7. D3 and D4 sold an equal number of Split Inverter ACs. This number was half the number of similar ACs sold by D2.
If D3 and D4 sold an equal number of ACs, then what was the number of Non-inverter ACs sold by D2?
Solution:
If D3 and D4 sold equal number of ACs, then the total number of ACs sold by D2 = 60 – (15 + 12 + 12) = 21.
Total number of Non-inverter ACs sold by D2 = 21 – 16 = 5.
If D3 and D4 sold equal number of ACs, then the total number of ACs sold by D2 = 60 – (15 + 12 + 12) = 21.
Total number of Non-inverter ACs sold by D2 = 21 – 16 = 5.
Solution:
Solution:
Solution:
Solution:
Solution:
Solution:
Solution:
Solution:
Solution:
Total number of households met by Tohri, Hokli and Lahur on day 1 = 10 + 49 + 25 = 84.
Total number of households met by Tohri, Hokli and Lahur on day 1 = 10 + 49 + 25 = 84.
Solution:
Total items sold by Tohri on day 1 = 40.
Total items sold by Tohri on day 1 = 40.
Solution:
Number of households visited by Lahur on day 2 = 25, which lies between 21 and 29.
Number of households visited by Lahur on day 2 = 25, which lies between 21 and 29.
Solution:
Tohri visited 10 households on day 1.
Tohri visited 10 households on day 1.
Solution:
Let us go by options (observe the success rates in the above table):
(1) Tohri had a higher success rate on the first day compared to the second day. This is true.
(2) Among the three, Tohri had the highest success rate on the second day. This is false.
(3) Among the three, Lahur had the lowest success rate on the first day. This is true.
(4) Among the three, Tohri had the highest success rate on the first day. This is true.
Let us go by options (observe the success rates in the above table):
(1) Tohri had a higher success rate on the first day compared to the second day. This is true.
(2) Among the three, Tohri had the highest success rate on the second day. This is false.
(3) Among the three, Lahur had the lowest success rate on the first day. This is true.
(4) Among the three, Tohri had the highest success rate on the first day. This is true.
Solution:
Number of students took AI = 210 + 60 = 270.
Number of students took AI = 210 + 60 = 270.
Solution:
Number of CS students failed in ML is 12.
Number of CS students failed in ML is 12.
Solution:
Number of non-CS students got A grade in ML is 27.
Number of non-CS students got A grade in ML is 27.
Solution:
Number of students got A grade in AI is 63 + 0 = 63.
Number of students got A grade in AI is 63 + 0 = 63.
Solution:
Number of non-CS students got B grade in ML is 75.
Number of non-CS students got B grade in ML is 75.
Solution:
D1 and D3 together sold 27 ACs whereas D2 and D4 sold 33 ACs. Hence, option (1) is necessarily false.
All the other statements are not necessarily false.
Hence, the correct answer is option (1).
D1 and D3 together sold 27 ACs whereas D2 and D4 sold 33 ACs. Hence, option (1) is necessarily false.
All the other statements are not necessarily false.
Hence, the correct answer is option (1).
Solution:
Total number of Split Inverter ACs sold by D2 = 14
Total number of Split Inverter ACs sold by D2 = 14
Solution:
Total number of ACs sold = 60; Total number of Non-inverter ACs sold = 15
Hence, required percentage = 15/60 x 100 = 25%.
Total number of ACs sold = 60; Total number of Non-inverter ACs sold = 15
Hence, required percentage = 15/60 x 100 = 25%.
Solution:
Total number of ACs sold by D2 and D4 = 60 – (15 + 12) = 33.
Total number of ACs sold by D2 and D4 = 60 – (15 + 12) = 33.
Solution:
If D3 and D4 sold equal number of ACs, then the total number of ACs sold by D2 = 60 – (15 + 12 + 12) = 21.
Total number of Non-inverter ACs sold by D2 = 21 – 16 = 5.
If D3 and D4 sold equal number of ACs, then the total number of ACs sold by D2 = 60 – (15 + 12 + 12) = 21.
Total number of Non-inverter ACs sold by D2 = 21 – 16 = 5.
