# CAT 2019 QA - Slot 2

Get the complete CAT 2019 paper with answers and explanations

## CAT 2019 Question Paper With Answers & Explanation

### QA

4

4

4

2

3

4

2

2

1

4

4

2

48

4851

1

150

4

3

3

13

44

2

3

20920

#### Q. 25 A cyclist leaves A at 10 am and reaches B at 11 am. Starting from 10:01 am, every minute a motor cycle leaves A and moves towards B. Forty-five such motor cycles reach B by 11 am. All motor cycles have the same speed. If the cyclist had doubled his speed, how many motor cycles would have reached B by the time the cyclist reached B?

3

###### Explanation

Since 45 motor cycles reach point B and 11 pm, the last motorcycle must have left at 10 : 45 and reached by 11 pm. So the whole journey takes 15 minutes to cover by motor cycle.
If cyclist doubles his speed, he will reach point B in 30 minutes. Since motorcycle takes 15 minutes to cover the distance, the first motorcycle reaches at 10 : 16 and in total 15 motor cycles would reach by when B reached.

#### Q. 26 In a six-digit number, the sixth, that is, the rightmost, digit is the sum of the first three digits, the fifth digit is the sum of first two digits, the third digit is equal to the first digit, the second digit is twice the first digit and the fourth digit is the sum of fifth and sixth digits. Then, the largest possible value of the fourth digit is

7

###### Explanation

As per the instruction, let the first digit be a.
The second digit will be 2a
Third digit will be a
Fourth digit will be (2a + 2b + a) = 7a
Fifth digit will be 3a
Sixth digit will be 4a
∴ Largest value of fourth digit can only be 7.

4

80

12

1

4

3