Question Numbers (1 to 5): An air conditioner (AC)
company has four dealers – D1, D2, D3 and D4 in a city.
It is evaluating sales performances of these dealers. The
company sells two variants of ACs – Window and Split.
Both these variants can be either Inverter type or Noninverter
type. It is known that of the total number of ACs
sold in the city, 25% were of Window variant, while the
rest were of Split variant. Among the Inverter ACs sold,
20% were of Window variant.
The following information is also known:
1. Every dealer sold at least two window ACs.
2. D1 sold 13 inverter ACs, while D3 sold 5 Non-inverter
ACs.
3. A total of six Window Non-inverter ACs and 36 Split
Inverter ACs were sold in the city.
4. The number of Split ACs sold by D1 was twice the
number of Window ACs sold by it.
5. D3 and D4 sold an equal number of Window ACs
and this number was one-third of the number of similar
ACs sold by D2.
6. D2 and D3 were the only ones who sold Window
Non-inverter ACs. The number of these ACs sold by
D2 was twice the number of these ACs sold by D3.
7. D3 and D4 sold an equal number of Split Inverter
ACs. This number was half the number of similar
ACs sold by D2.
Correct Answer
14
Explanation
Total number of Split Inverter ACs sold by D2 = 14
Correct Answer
2
Explanation
Total number of ACs sold = 60; Total number of
Non-inverter ACs sold = 15
Hence, required percentage = 15/60 x 100 = 25%.
Correct Answer
33
Explanation
Total number of ACs sold by D2 and D4
= 60 – (15 + 12) = 33.
Correct Answer
1
Explanation
D1 and D3 together sold 27 ACs whereas D2 and
D4 sold 33 ACs. Hence, option (1) is necessarily
false.
All the other statements are not necessarily false.
Hence, the correct answer is option (1).
Correct Answer
1
Explanation
If D3 and D4 sold equal number of ACs, then the
total number of ACs sold by D2
= 60 – (15 + 12 + 12) = 21.
Total number of Non-inverter ACs sold by D2
= 21 – 16 = 5.
Question Numbers (6 to 10): In a coaching class, some
students register online, and some others register offline.
No student registers both online and offline; hence the
total registration number is the sum of online and offline
registrations. The following facts and table pertain to these
registration numbers for the five months – January to
May of 2023. The table shows the minimum, maximum,
median registration numbers of these five months,
separately for online, offline and total number of
registrations. The following additional facts are known.
1. In every month, both online and offline registration
numbers were multiples of 10.
2. In January, the number of offline registrations was
twice that of online registrations.
3. In April, the number of online registrations was twice
that of offline registrations.
4. The number of online registrations in March was the
same as the number of offline registrations in
February.
5. The number of online registrations was the largest in
May.
Correct Answer
120
Explanation
Total number of registrations in April = 120
Correct Answer
40
Explanation
Online registrations in January = 40
Correct Answer
4
Explanation
The number of offline registrations in May was the
smallest, is true.
Total number of registrations in February was the
smallest, is false.
Hence, only statement I is true.
Correct Answer
1
Explanation
We can see from the table that the number of offline
registrations in February was 50.
Correct Answer
3
Explanation
It can be observed that January and April had 120
total registrations each and February and May had
130 total registrations each. Hence, both I and II
are correct.
Question Numbers (11 to 15): A, B, C, D, E and F are
the six police stations in an area, which are connected
by streets as shown below. Four teams – Team 1, Team
2, Team 3 and Team 4 –
patrol these streets continuously between 09:00 hrs.
and 12:00 hrs. each day.
The teams need 30 minutes to cross a street connecting
one police station to another. All four teams start from
Station A at 09:00 hrs. and must return to Station A by
12:00 hrs. They can also pass via Station A at any point
on their journeys.
The following facts are known.
1. None of the streets has more than one team
traveling along it in any direction at any point in
time.
2. Teams 2 and 3 are the only ones in stations E
and D respectively at 10:00 hrs.
3. Teams 1 and 3 are the only ones in station E at
10:30 hrs.
4. Teams 1 and 4 are the only ones in stations B
and E respectively at 11:30 hrs.
5. Team 1 and Team 4 are the only teams that patrol
the street connecting stations A and E.
6. Team 4 never passes through Stations B, D or F.
Correct Answer
2
Explanation
From the table we can see that station D was visited
twice, stations C and F were visited thrice and
station E was visited either 5 or 6 times. Hence,
station E was visited the maximum number of
times.
Correct Answer
2
Explanation
The number of times the teams pass through station
B = 2.
Correct Answer
3
Explanation
The team that is on route D-E at 10:15 is Team 3.
Correct Answer
2
Explanation
Team 4 passes through station E twice.
Correct Answer
1
Explanation
The number of teams that pass through station C
= 2.
Question Numbers (16 to 20): There are only three
female students – Amala, Koli and Rini – and only three
male students – Biman, Mathew and Shyamal – in a
course. The course has two evaluation components, a
project and a test. The aggregate score in the course is
a weighted average of the two components, with the
weights being positive and adding to 1.
The projects are done in groups of two, with each group
consisting of a female and a male student. Both the
group members obtain the same score in the project.
The following additional facts are known about the scores
in the project and the test.
1. The minimum, maximum and the average of both
project and test scores were identical – 40, 80 and
60, respectively.
2. The test scores of the students were all multiples of
10; four of them were distinct and the remaining two
were equal to the average test scores.
3. Amala’s score in the project was double that of Koli
in the same, but Koli scored 20 more than Amala in
the test. Yet Amala had the highest aggregate score.
4. Shyamal scored the second highest in the test. He
scored two more than Koli, but two less than Amala
in the aggregate.
5. Biman scored the second lowest in the test and the
lowest in the aggregate.
6. Mathew scored more than Rini in the project, but
less than her in the test.
Correct Answer
60
Explanation
Rini’s project score = 60.
Correct Answer
1
Explanation
Weight given to test scores = 0.6.
Correct Answer
1
Explanation
Maximum aggregate was for Amala and it was 68.
Correct Answer
40
Explanation
Mathew’s test score = 40.
Correct Answer
2
Explanation
The teams were (A, M), K, B) and (R, S).
Hence, neither (i) nor (ii) is correct.
